Assignment: Discussion Board: Independent vs Mutually Exclusive Events

Statistics: Spring 2022
2023-03-07T15:35:27Z

Due:

Instructions: Click "Reply" below this instruction set. You must reply with your initial post prior to seeing the posts of others. This Discussion Board is worth 60 points (30 points for the initial post, 15 for each reply post). In order to have EVERYONE get the opportunity to participate, you MUST complete this on time. If you are late on your initial post, you will therefor get (0%) zero credit for this discussion board.

1. Initial Post (Due Thursday, March 9): Create an example of either a Mutually Exclusive event or an Independent event using a deck of cards, fair dice, or fair coin. WITHOUT stating which you choose, create a prompt for your peers to view with a scenario that they must solve for the probability.

2. Peer Initial Reply Post (Due Monday, March 13): Define whether 1 peer's initial post is either mutually exclusive or independent and describe why using a sample space. Then solve their problem for the probability of the event occurring. (Note: you MUST reply to an initial post that HAS NOT received a reply yet. This seems to work BEST if you reply to the peer that replies to your post).

3. Final Reply Post (Due Wednesday, March 15): Create a Venn Diagram for your authored example to support your rationale of the event being mutually exclusive or independent. Reply to your initial authored post and provide your peer with constructive feedback of their analysis of your example. Provide the correct solution to your probability prompt with the correct answer to the event being either mutually exclusive or independent.

EXAMPLE Initial Post: (DON'T use this). What would be the probability to draw a card from a deck that would be (A)a Queen and (B) a Face-card?

EXAMPLE Peer Reply Post: "H" = HEART/ "C" = CLUB / "D" = DIAMOND / "S" = SPADE

Sample Space A{QH, QD, QS, QC}. Sample Space B{QH, QC, QD, QS ,JH, JC, JD, JS, KH ,KC ,KD ,KS }

P(A AND B) = P(A) + P(B) - P(A B)

P(A) = 4/52

P(B) = 16/52

P(A B) = 4/52

P(A B) = 4/52 + 16/52 - 4/52 = 16/52 = 8/26 = 4/13

HOW I GOT SUPERSCRIPTS & THE UNION SIGN:

Instructions: Click "Reply" below this instruction set. You must reply with your initial post prior to seeing the posts of others. This Discussion Board is worth 60 points (30 points for the initial post, 15 for each reply post). In order to have EVERYONE get the opportunity to participate, you MUST complete this on time. If you are late on your initial post, you will therefor get (0%) zero credit for this discussion board.

1. Initial Post (Due Thursday, March 9): Create an example of either a Mutually Exclusive event or an Independent event using a deck of cards, fair dice, or fair coin. WITHOUT stating which you choose, create a prompt for your peers to view with a scenario that they must solve for the probability.

2. Peer Initial Reply Post (Due Monday, March 13): Define whether 1 peer's initial post is either mutually exclusive or independent and describe why using a sample space. Then solve their problem for the probability of the event occurring. (Note: you MUST reply to an initial post that HAS NOT received a reply yet. This seems to work BEST if you reply to the peer that replies to your post).

3. Final Reply Post (Due Wednesday, March 15): Create a Venn Diagram for your authored example to support your rationale of the event being mutually exclusive or independent. Reply to your initial authored post and provide your peer with constructive feedback of their analysis of your example. Provide the correct solution to your probability prompt with the correct answer to the event being either mutually exclusive or independent.

EXAMPLE Initial Post: (DON'T use this). What would be the probability to draw a card from a deck that would be (A)a Queen and (B) a Face-card?

EXAMPLE Peer Reply Post: "H" = HEART/ "C" = CLUB / "D" = DIAMOND / "S" = SPADE

Sample Space A{QH, QD, QS, QC}. Sample Space B{QH, QC, QD, QS ,JH, JC, JD, JS, KH ,KC ,KD ,KS }

P(A AND B) = P(A) + P(B) - P(A B)

P(A) = 4/52

P(B) = 16/52

P(A B) = 4/52

P(A B) = 4/52 + 16/52 - 4/52 = 16/52 = 8/26 = 4/13

HOW I GOT SUPERSCRIPTS & THE UNION SIGN: